7. Consider the reaction: Cr2O72 + 14H+ + 6e- —> 2Cr3+ + 7H2O what is the quantity of electricity in coulombs needed to reduced 1 mol of Cr2O72 ?

7. Consider the reaction: Cr2O₇² + 14H⁺ + 6e^- —> 2Cr³⁺ + 7H2O what is the quantity of electricity in coulombs needed to reduced 1 mol of Cr2O₇² ?

SOLUTION

asked: what is the quantity of electricity in coulombs needed to reduced 1 mol of Cr2O₇² ?

answer:

Cr2O₇² + 14H⁺ + 6e^- —> 2Cr³⁺ + 7H2O

Q/F = mol . Vf . F

Q/F = mol. Vf. F

Q = 1 . 6 . 96500

Q = 5,79x10⁵ C