A solution consists of 0.2M NH4OH and 0.2M NH4Cl. If Kb of NH4OH is 1.8 × 10^5, the [OH-] of the resulting solution is ?

A solution consists of 0.2M NH4OH and 0.2M NH4Cl. If Kb of NH4OH is 1,8x10-5, the [OH-] of the resulting solution is ?
A. 3,6x10-5
B. 3,2x10-5
D. 1,8x10-5
C. 0,9x10-5

SOLUTION


NH4OH and NH4Cl is a buffer solution:
POH = PKb + log [salt]/[base]
Concentration of NH4OH = 0,2 M
Concentration of NH4Cl = 0,2 M
PKb of NH4OH = 1,8x10-5      

POH = - log 1,8x10-5 + log [0,2]/[0,2]
POH = - log 1,8x10-5  
-log [OH-] = - log 1,8x10-5 
[OH-] = 1,8x10-5
well, the concentration of [OH-] is 1,8x10-5

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