Ionisation constant of CH3COOH is 1,7×10⁻⁵and concentration of H+  ions is 3,4×10-4. Then find out initial concentration of CH3COOH molecule ?SOLUTIONKnown:CH3COOH = 1,7x10-5H+ = 3,4×10-4Asked: concentration of CH3COOH molecule ?CH3COOH —> CH3COO⁻ + H+x                   3,4x10-4         3x10-4K = [CH3COO-] [H+]/[CH3COOH]1,7x10-5 = [3,4x10-4] [3,4x10-4]/xx = 6,8x10-3so, the concentration of CH3COOH molecule...

3. An aqueous solution contains 0.01M RNH₂ ( Kb = 2x10-6 ) & 10-4 M NaOH. The concentration of OH- is nearly ?A. 2.414×10-4 B. 2×10-4 C. 1.414×10-5D. 10-4 E. 1.414×10-4 SOLUTION[OH−] ⟹ RNH2​ is weak base, it reacts with H2​OpKb​ = −log1​0 (2×10-6) = 6 − log2pH = 14 − 21​ (pKb​ − logC)pH = 14 − 21​ (6-log2 − log10−2)pH = 14 − 3...